(5xy^3)(3x^4y^2)-(2x^3y)(x^2y^4)=0

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Solution for (5xy^3)(3x^4y^2)-(2x^3y)(x^2y^4)=0 equation:


Simplifying
(5xy3)(3x4y2) + -1(2x3y)(x2y4) = 0

Remove parenthesis around (5xy3)
5xy3(3x4y2) + -1(2x3y)(x2y4) = 0

Remove parenthesis around (3x4y2)
5xy3 * 3x4y2 + -1(2x3y)(x2y4) = 0

Reorder the terms for easier multiplication:
5 * 3xy3 * x4y2 + -1(2x3y)(x2y4) = 0

Multiply 5 * 3
15xy3 * x4y2 + -1(2x3y)(x2y4) = 0

Multiply xy3 * x4y2
15x5y5 + -1(2x3y)(x2y4) = 0

Remove parenthesis around (2x3y)
15x5y5 + -1 * 2x3y(x2y4) = 0

Multiply -1 * 2
15x5y5 + -2x3y * x2y4 = 0

Multiply x3y * x2y4
15x5y5 + -2x5y5 = 0

Combine like terms: 15x5y5 + -2x5y5 = 13x5y5
13x5y5 = 0

Solving
13x5y5 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '13'.
x5y5 = 0

Simplifying
x5y5 = 0

The solution to this equation could not be determined.

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